[jython]スクリプト名の取得

落ち着いて聞いて欲しい

scName=sys.argv[0]

これだけで済むはずのコードが

cmdline = os.environ.get('IBM_JAVA_COMMAND_LINE')
if up1frame == topframe and cmdline and not topframe.f_globals.get('__file__'):
    beg = 0
    end = len(cmdline)
    # Throw away everything after the '--', if present.
    dashdash = cmdline.find('--', beg, end)
    if dashdash >= 0:
        end = dashdash
    # If we can't find a filename, just use a "-"
    mainfile = '-'
    dashf = cmdline.rfind(' -f ', beg, end)
    if dashf:
        # Grab everything from after the "-f" to the following space.
        beg = dashf + 4
        space = cmdline.find(' ', beg, end)
        if space >= 0:
            end = space
        mainfile = cmdline[beg:end]

scName=mainfile

websphere V7 のjythonではこうなる。
はっきり言って役に立つとは思えないが
血圧増加大な効果を喰らうのは俺だけでいい。
参考までに記録しておく

http://dbrand666.wordpress.com/2010/04/13/fix5/
http://alvinabad.wordpress.com/2008/05/28/jython-in-webspheres-wsadmin-broke-sysargv/